We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle.
Answer:
Use SAS to show that triangles PRQ and PRS are congruent.
Step-by-step explanation:
Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.
We can use the Pythagorean theorum
a^2+b^2=c^2
c^2 is the length of the longest side squared
so
6^2 + b^2 = 10^2
36+ b^2 = 100
-36 -36
b^2 = 64
b = 8
b is the same thing as your "x", so x = 8
Simple; you want to divide 3 and 8.
3 / 8 = 0.375
And there's your answer! Remember that a fraction is just a fancy division problem! :)
