9514 1404 393
Answer:
B. 4
Step-by-step explanation:
Equating exponents, we have ...
2x +7 = 15
2x = 8 . . . . . subtract 7
x = 4 . . . . . . divide by 2
The equation is true when the value of x is 4.
Answer:
12,39,21,18,24,17,12,25
Step-by-step explanation:
5X^4 + 2X^2 – 8
Its quadratic form is 5(x²)² +2x² -8
<span>Let be X²=p, so the final expression is 5p²+2p-8</span>
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
