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Mariana [72]
2 years ago
5

PLEASE SOLVE WILL GIVE BRAINLIEST IF RIGHT

Mathematics
1 answer:
wlad13 [49]2 years ago
3 0

Answer: It would be (3)1

Step-by-step explanation:

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3 years ago
The lengths of pregnancies in a small rural village are normally distributed with a mean of 265 days and a standard deviation of
MakcuM [25]

Answer:

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

Step-by-step explanation:

Given that :

Mean  = 265

standard deviation = 14

The formula for calculating the z score is z = \dfrac{x -\mu}{\sigma}

x = μ + σz

At middle of 50% i.e 0.50

The critical value for z_{\alpha/2} = z_{0.50/2}

From standard normal table

z_{0.25}= + 0.67  or -0.67  

So; when z = -0.67

x = μ + σz

x = 265 + 14(-0.67)

x = 265 -9.38

x = 255.62

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x = μ + σz

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x = 265 + 9.38

x = 274.38

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

3 0
3 years ago
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