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oksano4ka [1.4K]
3 years ago
14

Find the slope and y-intercept of the line.

Mathematics
1 answer:
worty [1.4K]3 years ago
6 0
Using the slope-intercept form, the slope of the line is 1 (Imagine there is a 1 in front of the x) and the y-intercept is -5. The answer is D.
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Brian bought a desk on sale for $536. This price was 33% less than the original price.
Brilliant_brown [7]
The original price is $1624.242424 more than likely it was $1,624.25.
6 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!
bezimeni [28]
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5 0
3 years ago
Read 2 more answers
slader (a) Find parametric equations for the line through (4, 1, 8) that is perpendicular to the plane x − y + 4z = 2. (Use the
Pavel [41]

Answer:

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

xy - plane    (x, y, z) = (2, -1, 0)

yz - plane    (x, y, z) = (0, 5, -8)

xz - plane     (x, y, z) = (5, 0, 12)

Step-by-step explanation:

The given point (x, y ,z) = (4, 1, 8)

The plane x -y + 4z = 2

Normal vector (n) = < 1, -1, 4 >

The equation of line through point (4, 1, 8) and the plane is:

(x(t), y(t), z(t)) = (4, 1, 8) + t(1, -1, 4)

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

Any point on the line P(x, y, z) = ( 4 + t, 1 - t, 8 + 4t)

xy-Pane ⇒ z = 0

8 + 4t = 0

4t = - 8

t = -8/4

t = -2

∴

(x, y, z) = (4 - 2, 1 - 2, 8 + 4(-2))

(x, y, z) = (2, -1, 0)

yz-plane ⇒ x = 0

4 + t = 0

t = -4

∴

(x, y, z) = (4 + (-4) , 1-(-4), 8 + 4(-4)

(x, y, z) = (0, 5, -8)

xz-plane ⇒ y = 0

1 - t = 0

-t = -1

t = 1

∴

(x, y, z) = ( 4 + 1, 1 - 1, 8 + 4(1) )

(x, y, z) = (5, 0, 12)

6 0
3 years ago
(X,3) , (5,9) slope=2
maxonik [38]
Equation for slope.
y2 - y1/x2 - x1
Using (x,3) and (5,9)
9 - 3/5 - x = 2
6/(5 - x) = 2
Cross multiply
6 = 2(5 - x)
6 = 10 - 2x
6 - 10 = -2x
-4 = -2x
x = 2
y2 - y1/x2 - x1
9 - 3/5 - 2
6/3 = 2
Hope this helps.
:-)

5 0
3 years ago
Solve for c. ! PLEASE SOLVE !
Strike441 [17]

theres no real way to solve that because of B have you asked one else about this question you cant solve this with a expression.


3 0
3 years ago
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