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murzikaleks [220]
3 years ago
15

Which function represents the data in the table ?

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0
The answer is D
f(x) = 3x + 1
7nadin3 [17]3 years ago
6 0

Answer:

D

Step-by-step explanation:

X |  Y

-2   -5

-1    -2

0      1

1       4

2       7

4      13

y2 -y1 =

x2 -x1 =

Pick any two points  -2 -  -5 = 3

                                  -1  - -2  = 1

Each one will come out to 3/1   ..... even simplify if needed   practice  the others :)

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Licemer1 [7]

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8 0
3 years ago
Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re
attashe74 [19]

Answer: \frac{11}{15}

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

LCM=5*3=15

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}

7 0
3 years ago
Help me please,Thanks
mylen [45]
D 66 cats

Hope this helps!
7 0
3 years ago
Solve for p P-17=2p+3
Y_Kistochka [10]

Answer:

-20

Step-by-step explanation:

P-17=2P+3

P-2P=17+3

-P=20

Divide both sides by negative 1

P=20

7 0
3 years ago
The mean number of children among a sample of 15 low-income households is 2.8. The mean number of children among a sample of 19
gtnhenbr [62]

Answer:

Step-by-step explanation:

Let's put the data as below:

n1=15    x1=2.8      s1=1.6       and s1²=2.56

n2=19   x2=2.4     s2=1.7        and s2²=2.89

alpha= 0.05

To test the hypothesis:

H0= There is no sufficient evidence that low income household have fewer children

H1=There is sufficient evidence that low income household have fewer children

Assume that population variances are equal.

the t-static for two samples,

t=\frac{x1-x2}{Sp\sqrt{\frac{1}{n1}-\frac{1}{n2} \\} } } ~t with min (n1-1,n2-1)df

The pooled variance estimate Sp equals:

Sp^{2}=\frac{(n1-1)s1^{2}+(n2-1)s2^{2}  }{n1+n2-2}

Sp²=2.7456

Sp=1.65699

Degrees of freedom=n1+n2-2=32

Under null hypothesis:

tcal=\frac{|2.8 - 2.4|}{1.6599\sqrt{\frac{1}{15}+\frac{1}{19}  } }

tcal=0.6989

The critical value ttab=2.0369 for alpha=0.05

So we reject our null hypothesis H0

So there is sufficient evidence that low income households have fewer children than high income households

6 0
3 years ago
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