Given:
Two similar rectangles.
To find:
The area of the larger rectangle.
Solution:
Let x be the other side of the larger rectangle.
Corresponding sides of similar figures are always congruent.
The other side of larger rectangle is 2 cm.
We know that, area of rectangle is
So, area of the larger rectangle is
Therefore, the area of the larger rectangle is 8 sq. cm.
Square root of 121 is 11.
11-7=4
A side of the original square is 4 feet.
Cotx = cosx/sinx
cscx = 1/sinx
If we plug these into your equation we get:
(cosx/sinx)/(1/sinx) - 1
Dividing by a number is the same as multiplying by its reciprocal so it can be rewritten as:
(cosx/sinx)(sinx) - 1
The two sinx's cancel each other out so we end up with cosx - 1
What are you trying to find? y?x?..???
