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3 years ago

12

Josh pulled cards from a deck 200 times. He pulled a red card 120 times and a black card 80 times. What is the experimental prob

ability that the next card is black? Remember to simplify.

1 answer:

Ber [7]3 years ago

8 0

The answer is 2/3 because you would put 80 over 120 and simplify

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The length of arc PR is 12 centimeters and its measure is 60° on circle O.

Leto [7]

Answer:

originally I had planned on getting the car today and it to

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2 years ago

Anyone know the answer to any of these.

skad [1K]

A is c=75 B is a=120 C is b= square root of 75 and D= square root of 245

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4 years ago

The slope-intercept form of the equation of a line that passes through the point (4, -3) is y=-3x+5. What is the point-slope for

rewona [7]

Answer:

y+ 3 = -1/3 (x-4)

Step-by-step explanation:

Simply plug in the values using (4, -3)

4 = x₁

-3 = y₁

Now one rule to keep in mind when plugging it in, since a negative and a negative make a positive, you have to add three instead of subtracting it.

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4 years ago

Read 2 more answers

What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34

Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30 given

a1 = 6 given

t30 = 209 calculated from step 2

Sum = (a1 + t30)*n/2 Substitute

Sum = (6+ 209)*30/2 Combine like terms and divide by 2

sum = 215 * 15 Multiply

Sum = 3135 Answer

4 0

3 years ago

SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council

fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = $\frac{x-1100}{200}$

$P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517$

4 0

4 years ago