How to solve these 3 radical expressions. I’m confused and would appreciate it if you could show your work. Thanks!
1 answer:
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P(defective) = 3/12 = 1/4
P(good) = 1 - 1/4 = 3/4
The probability that at least 2 units are good is given by:
P(2 good) + P(3 good) + P(4 good) = 0.211 + 0.422 + 0.316 = 0.949.
P(good) = 1 - 1/4 = 3/4
The probability that at least 2 units are good is given by:
P(2 good) + P(3 good) + P(4 good) = 0.211 + 0.422 + 0.316 = 0.949.