The radical equation is

.
i) We first isolate the square root, adding 5 to both sides of the equation:

ii) Here let's substitute x+6 with t. Doing so we have:

Squaring both sides, we get:

iii) Collecting the variables on the same side, and factorizing t we have:

, which yields
t=0 or t=1.
Now we solve for x in x+6=t:
x+6=0 ⇒x=-6 and x+6=1⇒x=-5.
iv) Now we check these values in the original equation

:
a)

⇒ 0=0 ; Correct.
b)

⇒ 1=1 ; Correct.
Answer: <span>x = −6 and x = −5 </span>
You just combine like terms so it'll be 5x^43
Answer: f(x) = -ln(x + 1) + 3
Step-by-step explanation:
We want it to be decreasing, then we can write it, for a start, as:
f(x) = -ln(x)
Ok, now we want it to have a positive y intercept, then we can add a real number inside the logarithm, and other outside: such that f(0) = positive number.
f(x) = -ln(x + 1) + 3
Now, when x = 0 we have:
f(0) = -ln(1) + 3 = 0 + 3 = 3
Then we have a decreasing logarithmic function, with an y-intercept larger than zero.
D=rt
r=d/t
divide by t to sinlge out r