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NemiM [27]
3 years ago
13

Helppp someone!! I’m giving brainliests to everyone

Mathematics
1 answer:
Annette [7]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

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Find the non-extraneous solutions of the square root of the quantity x plus 6 minus 5 equals quantity x plus 1.
sdas [7]
The radical equation is \sqrt{x+6}-5=x+1.


i) We first isolate the square root, adding 5 to both sides of the equation: 
       
                                        \sqrt{x+6}=x+6.

ii) Here let's substitute x+6 with t. Doing so we have:
 
                                         \sqrt{t}=t.

Squaring both sides, we get:
                       
                                               t=t^2

iii) Collecting the variables on the same side, and factorizing t we have:
 
                                               t(t-1)=0, which yields

                              t=0    or       t=1.

Now we solve for x in x+6=t:

x+6=0 ⇒x=-6       and x+6=1⇒x=-5.


iv) Now we check these values in the original equation  \sqrt{x+6}=x+6 :

a) \sqrt{-6+6}=-6+6. ⇒ 0=0 ; Correct.


b) \sqrt{-5+6}=-5+6. ⇒ 1=1 ; Correct.



Answer: <span>x = −6 and x = −5 </span>
5 0
3 years ago
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Simplify. (x3)5 5x3 x15 x2 x8
maks197457 [2]
You just combine like terms so it'll be 5x^43
3 0
3 years ago
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Give an example of a decreasing logarithmic function that has a positive y-intercept.
Anvisha [2.4K]

Answer: f(x) = -ln(x + 1) + 3

Step-by-step explanation:

We want it to be decreasing, then we can write it, for a start, as:

f(x) = -ln(x)

Ok, now we want it to have a positive y intercept, then we can add a real number inside the logarithm, and other outside: such that f(0) = positive number.

f(x) = -ln(x + 1) + 3

Now, when x = 0 we have:

f(0) = -ln(1) + 3 = 0 + 3 = 3

Then we have a decreasing logarithmic function, with an y-intercept larger than zero.

3 0
3 years ago
Solve for r: d = rt
dlinn [17]
D=rt
r=d/t
divide by t to sinlge out r
8 0
3 years ago
What is the answer for this question
Lady_Fox [76]
The answer is 1 5/10.
6 0
4 years ago
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