Each of the five school buses can hold 43 pupils.

Consider f(x) = 1.8x – 10 and g(x) = −4.

Pavlova-9 [17]

Answer:

Part 1) The equation that can be used is 1.8x-10=-4

Part 2) The input or x-value is x=10/3

Step-by-step explanation:

we have

f(x)=1.8x-10

g(x)=-4

To find the solution of the system of equations equate f(x) and g(x)

f(x)=g(x)

substitute

1.8x-10=-4 -----> equation that can be used to find the input value at which f (x ) = g (x )

Solve for x

Adds 10 both sides

1.8x=-4+10

1.8x=6

Divide by 1.8 both sides

x=6/1.8

Remember that

1.8=18/10

substitute

x=6/(18/10)

x=60/18

Simplify

x=10/3

8 0

3 years ago

The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16

dusya [7]

Answer:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

$n_1 = 16$ represent the sampe size 1

$n_2 =16$ represent the sample 2

$s^2_1 = 2.5$ represent the sample deviation for 1

$s^2_2 = 5.5$ represent the sample variance for 2

$\alpha=0.10$ represent the significance level provided

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \neq \sigma^2_2$

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

5 0

3 years ago

The average of 6 numbers is 7. When a 7th number is addedThe average of all numbers is 0. What is the seventh number?

Katena32 [7]

-- The average of 6 numbers is 7.
    So those 6 numbers must add up to 42.

-- If one more number results in an average of zero,
   the new number must be -42 .
   Then all 7 numbers add up to zero.

4 0

3 years ago

Express the height of the following rectangular prism in meters. (Note: 1 m = 100 cm)

3241004551 [841]

Answer:I did this one and its 0.75

Step-by-step explanation:

4 0

3 years ago

Round 492.3069 to the nearest thousandth

Llana [10]

The answer is 492.307
The number after the thousandths is 9 - greater than 5 - so we round 6 up to 7.

4 0

3 years ago