Answer:
The length of each side of the 9 in
Step-by-step explanation:
The volume of the gift box is 972 in. The height of the gift box is 12 inches
and the area of the base is 81 in².
We want to determine the length of each side of the square base if the base shape is a square.
Recall that, the area of a square is
It was given that, the area of this base is 81 in²
Take positive square root:
The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)
The given system of equations is:
Equate equations (1) and (2)
Solve for x in the equation above
Substitute x = 7 into equation (1)
The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)
Learn more on system of equations here: brainly.com/question/13729904
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
- Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
- Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
- Finally we add up the following shapes Volume which are 6160+420=6580cm
Answer:
1 solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
9(z + 8) = -9z - 72
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 9: 9x + 72 = -9z - 72
- Add 9z to both sides: 18z + 72 = -72
- Subtract 72 on both sides: 18z = -144
- Divide 18 on both sides: z = -8
Here we see that we will get only 1 solution for <em>z</em>.
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
