All categories

2 years ago

!!WILL MARK BRAINLIEST!!

Mathematics

2 answers:

masya89 [10]2 years ago

8 0

Answer:

6 feet

Step-by-step explanation:

Formula: V=1/3Bh

V=1/3(4×4)6

V=1/3(16)6

V=1/3(96)

V=96÷3

V=32

(P.S.-The capital 'B' in the formula stands for the area of the square base)

Hope this helped :)

iren2701 [21]2 years ago

3 0

Answer:

4) 8

Step-by-step explanation:

You might be interested in

Enter the absolute value of 6.2 and -7/2

CaHeK987 [17]

Answer:

1, 6.2 and 7/2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.

puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

$A=\dfrac{a+b}{2}h$

Where, $a,b$ are parallel sides and $h$ is the vertical distance between the parallel sides.

Putting $a=28.7, b=22.3,h=16$ in the above formula, we get

$A=\dfrac{28.7+22.3}{2}\times(16)$

$A=\dfrac{51}{2}\times 16$

$A=51\times 8$

$A=408$

Therefore, the area of the trapezium is 408 square cm.

4 0

3 years ago

What are the domain and range of the function below?

irina1246 [14]

I think the answer is

domain : (- infinity , infinity )

range : [ -2 , infinity )

i am sorry if my answer was wrong

8 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago

From 1980 to 1990, the consumer price index (CPI) increased from 82.4 to 130.7. If a gallon of apple juice cost $0.95 in 1980 an

ryzh [129]

Answer: C $1.51

To solve this, start with a proportion. Put the CPI numbers on the left and the apple juice prices on the right.

You will have:

82.4/130.7 = 0.95/x

Cross multiply to solve and you will get the price of the juice is $1.51.

4 0

3 years ago

Read 2 more answers