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Elenna [48]
3 years ago
12

Someone please help me thank you

Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0
This is how you graph the question

Ksju [112]3 years ago
3 0

Answer:

Screenshot of graph image.

Step-by-step explanation:

Correction to the previous answer. You need to graph the line.

Extra Information:

The Linear Equation Is y=\frac{2}{3} x+-4

The Slope Is \frac{2}{3}

The Y Intercept Is -4

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Simplify the expression completely.
ivolga24 [154]
You can’t simplify it any further. 288 1/4 is already simplified.
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3 years ago
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Corinna has $80. She wants to buy a $256 plane ticket. She will save up her earnings from working at the museum where she earns
Gnesinka [82]

Answer:8

Step-by-step explanation:

8 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
4+(-7) what is the solution
MrMuchimi

Answer:

-3

Step-by-step explanation:

8 0
3 years ago
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Find the value of x. Round to the nearest tenth.
Reika [66]
Using SOH CAH TOA, you have the Opposite side and you need to work out the Hypotenuse so you will use SOH. This means that the opposite divided by the sine of the angle is the hypotenuse: 18/sin(35) = x = 31.4
4 0
4 years ago
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