Ask question

Ask question

All categories

3 years ago

13

Find two ratios equivalent to the ratio in Exercise 1.

1 answer:

pshichka [43]3 years ago

8 0

Answer:

12:26, 24:52 :D

You might be interested in

Which is greater, 5/6, 7/8 or 5/8?

Mashutka [201]

5/6 i think it’s that

7 0

3 years ago

Read 2 more answers

Would you solve this by multiplying the second equation by 2 or -2 and why?

alexandr1967 [171]

What’s the equation?

6 0

3 years ago

Read 2 more answers

Pls help will mark as brainliest

Alchen [17]

It is Consistent sorry if wrong

3 0

3 years ago

Add<br><br>4cosec 0+cosec 0+cosec 0+2cosec 0<br><br>step by step.

zvonat [6]

4cosec 0+cosec 0 + cosec 0 + 2 cosec 0

8 cosec 0

4 0

3 years ago

Read 2 more answers

Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8

san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

$\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}$

Firstly, we will factor both denominators

$b^2-64=b^2-8^2=(b-8)(b+8)$

$b^2+7b-8=(b+8)(b-1)$

so, we can plug it back

$\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}$

First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

$LCD=(x-8)(x+8)(x-1)$

3 0

3 years ago