If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
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Answer:
a = 10
Step-by-step explanation:
From the solution given, x = a and y = -1
Substitute for x and y in either of the equations
y = -x + 9
-1 = -a + 9
a = 9 + 1 = 10
Answer:
10+2+0.3+0.05+0.007
Step-by-step explanation:
Answer:
x = - 7, y = 6
Step-by-step explanation:
7x + 7y = - 7 -----> equation 1
- 10x - 7y = 28 -----> equation 2
Add equations 1 & 2,
7x + 7y = - 7
- 10x - 7y = 28
___________
- 3x + 0 = 21
- 3x = 21
x = 21 / - 3
x = - 7
Substitute x = - 7 in equation 1,
7x + 7y = - 7
7y + 7x = - 7
7y + 7 ( - 7 ) = - 7
7y - 49 = - 7
7y = - 7 + 49
7y = 42
y = 42 / 7
y = 6
