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Alexxx [7]
3 years ago
9

Melanie invested $3,800 in an account paying an interest rate of 2% compounded

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0

Answer:

101

Step-by-step explanation:

aleksley [76]3 years ago
7 0

Answer:101

Step-by-step explanation:

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I have to simplify this. It says assume that all variables in the variable in the denominator are nonzero. Leave your answer in
ra1l [238]
I wish I could help u but I can’t
7 0
3 years ago
Point A is located at (−2, −6), and D is located at (−6, 8). Find the coordinates of the point that lies halfway between A and D
Afina-wow [57]

Answer:

(-4,1)

Step-by-step explanation:

Point A is located at (−2, −6), and D is located at (−6, 8).

We need to find the midpoint of A  and D

Mid point formula is (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Point A is (-2,-6) that is (x1,y1)

Point D is (-6,8) that is (x2, y2)

plug in the values in the formula

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

(\frac{-2-6}{2}, \frac{-6+8}{2})

(\frac{-8}{2}, \frac{2}{2})

Mid point is (-4, 1)

5 0
3 years ago
Read 2 more answers
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
Find the derivative of StartFraction d Over dx EndFraction Integral from 0 to x cubed e Superscript negative t Baseline font siz
Valentin [98]

Answer: (a) e ^ -3x (b)e^-3x

Step-by-step explanation:

I suggest the equation is:

d/dx[integral (e^-3t) dt

First we integrate e^-3tdt

Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.

(b) to differentiate the integral let x = t, and substitute into the expression.

Therefore dx = dt

Hence, d/dx[integral (e ^-3x dx)] = e^-3x

8 0
3 years ago
Read 2 more answers
2(m-n^2)-6(n^2+3m) simplify by like terms
umka2103 [35]
2(m-n^2)-6(n^2+3m)
=2m-2n^2-6n^2+18m
=20m-8n^2


Done ✅ Hope it helps
5 0
3 years ago
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