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Umnica [9.8K]
3 years ago
6

The function f(x) varies inversely with x and f(x) = 0.9 when x = 0.5 what is f(x) when x = 1.5 ?

Mathematics
2 answers:
marin [14]3 years ago
4 0
When x = 0.5, the answer is 0.45
When x = 1.5, the answer is 1.35

You're welcome :)
vlada-n [284]3 years ago
4 0

Answer:

the answer is 0.3

Step-by-step explanation:

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The sum is -3.3z - 11
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Write the equation of the line that passes through the points (8,9)
mart [117]

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in total it will be 3

Step-by-step explanation:

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280 miles in 4 hours 816 miles in 12 hours how are the ratios set up
nirvana33 [79]

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180:4 and 816:12

Step-by-step explanation:

7 0
2 years ago
Find all values of c such that f is continuous on (-[infinity], [infinity]). f(x) = { 3 - x^2 x less than or equal to c x, x &gt
yuradex [85]

Answer:

a) c=\frac{-1+\sqrt{13}}{2} and c=\frac{-1-\sqrt{13}}{2}

Step-by-step explanation:

The idea for the solution of this equation is to find the value of c where both parts of the piecewise-defined function are the same. So we need to take the parts of the function and set them equal to each other, so we get:

3-x^{2}=x

and then solve for x. We move everything to one side of the equation so we get:

x^{2}+x-3=0

and we use the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

and we substitute:

x=\frac{-1\pm \sqrt{(1)^2-4(1)(-3)}}{2(1)}

and solve

x=\frac{-1\pm \sqrt{1+12}}{2}

x=\frac{-1\pm \sqrt{13}}{2}

so our two answers are:

a) c=\frac{-1+\sqrt{13}}{2} and c=\frac{-1-\sqrt{13}}{2}

6 0
3 years ago
The populations P (in thousands) of a certain town in North Carolina, from 2006 through 2012 can be modeled by
Ksju [112]

Answer:

Step-by-step explanation:

Given the populations P (in thousands) of a certain town in North Carolina, from 2006 through 2012 modeled by

P = 5.5e^kt,

If in 2008, the population was 7000. then;

at t = 2, P = 7000

7 = 5.5e^2k

7/5,5 = e^2k

1.2727= e^2k

Apply ln to both sides

ln 1.272 = lne^2k

ln 1.272= 2k

0.2411 = 2k

k = 0.2411/2

k = 0.1206 (to 4dp)

By 2018, the time t = 12 (2006-2018)

Substitute

P = 5.5e^(0.1206)(12)

P = 5.5e^(1.4468)

P = 5.5(4.2495)

P = 23.3722

P = 23372

Hence the population after 12 years is approx 23,372 populations

4 0
3 years ago
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