All categories

3 years ago

The function f(x) varies inversely with x and f(x) = 0.9 when x = 0.5 what is f(x) when x = 1.5 ?

Mathematics

2 answers:

marin [14]3 years ago

4 0

When x = 0.5, the answer is 0.45
When x = 1.5, the answer is 1.35

You're welcome :)

vlada-n [284]3 years ago

4 0

Answer:

the answer is 0.3

Step-by-step explanation:

You might be interested in

You're working with a customer that's interested in buying a keyboard that costs 250 dollars. They want to know what their total

rusak2 [61]

Answer:

I think it is 3.5

Step-by-step explanation:

8.5:250*100 =

(8.5*100):250 =

850:250 = 3.4

3 0

3 years ago

What is set? Mark as brainiest

Setler [38]

Answer:

collection of objects

Step-by-step explanation:

set is a collection of objects, things or figures.

7 0

3 years ago

Read 2 more answers

Please help this is due soon

NikAS [45]

Answer:

c=42

Step-by-step explanation:

6 0

3 years ago

Complete the table. table Distances:

Sever21 [200]

Answer:79

Step-by-step explanation:78: I love the noise

5 0

3 years ago

Read 2 more answers

Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. 1 choice: P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

2 choice: P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

5 0

3 years ago

Read 2 more answers