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3 years ago

Can someone help me with this equation

Mathematics

1 answer:

Alexxandr [17]3 years ago

6 0

Answer:

D) y=250-6x

Step-by-step explanation:

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Please help please help please help !!!!!!!

Shtirlitz [24]

Answer:

Step-by-step explanation:

The graph below shows what you are given. The equation is actually y = x-4

3 0

3 years ago

PLS HELP I’LL MARK BRAINLIEST!!! ALSO THE ANSWER IS NOT 118!

Ainat [17]

Answer:

B. 128

Step-by-step explanation:

so the sum of the interior angle is 180

180 - 76 is 104

since both sides are the same divide 104 with 2 to get 52

to find x = 180 - 52 = 128

3 0

3 years ago

How many solutions are there to the equation below? <br><br> 8x-10=3(2x+5)+2x

pishuonlain [190]

Answer:

No solutions

Step-by-step explanation:

8x - 10 = 3(2x + 5) + 2x

8x - 10 = 6x + 10 + 2x

8x - 10 = 8x + 10

4 0

2 years ago

Find the values of x and y in the diagram.

MrRissso [65]

Answer:

wheres the diagram?

Step-by-step explanation:

need the diagram in order to answer the question

8 0

3 years ago

Orthogonally diagonalize the matrix, giving an orthogonal matrix P and a diagonal matrix D. To save time, the eigenvalues are

alexgriva [62]

Answer:

$P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)$

Step-by-step explanation:

It is a result that a matrix $A$ is orthogonally diagonalizable if and only if $A$ is a symmetric matrix. According with the data you provided the matrix should be

$A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)$

We know that its eigenvalues are $\lambda_{1}=-14, \lambda_{2}=-5$ , where $\lambda_{2}=-5$ has multiplicity two.

So if we calculate the corresponding eigenspaces for each eigenvalue we have

$E_{\lambda_{1}=-14}=\langle(-2,-2,1)\rangle$ , $E_{\lambda_{2}=-5}=\langle(1,0,2),(-1,1,0)\rangle.$ .

With this in mind we can form the matrices $P, D$ that diagonalizes the matrix $A$ so.

$P=\left(\begin{array}{ccc}-2&-2&1\\1&0&2\\-1&1&0\\\end{array}\right)$

and

$D=\left(\begin{array}{ccc}-14&0&0\\0&-5&0\\0&0&-5\\\end{array}\right)$

Observe that the rows of $P$ are the eigenvectors corresponding to the eigen values.

Now you only need to normalize each row of $P$ dividing by its norm, as a row vector.

The matrix you have to obtain is the matrix shown below

3 0

4 years ago