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kenny6666 [7]
3 years ago
13

PLZ HELP ME!!!!!!!!!!!

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0
WAT SCHOOL U GO TO AND GRADE 

POLL 1. D
POLL 2. D
POLL 3. A
POLL 4. A
POLL 5. C
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Pie

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Sarah bought 3 first class tickets and 3 coach tickets.

Step by Step Explanation:

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3 years ago
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

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Also putting t=0 into equation (3)

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The system of first order equations is:

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3 0
3 years ago
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grigory [225]

Answer and Step-by-step explanation:

The answer is the last answer choice.

g(x) = -(x + 2)^2 + 1

We don't even have to look at the numbers to tell that this is the correct answer. We look at what is being placed there.

The equation for a transformed function is:

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a determines the scale of the graph and whether the graph opens up or down.

h determines whether the graph shifts left or right.

k determines whether the graph shifts up or down.

We see that there is a -1 for a, which means the graph will be facing downwards. We see a 2 for where h is, but it really is a -2, and when it becomes a positive after simplifying, the graph will shift to the left.

k is a positive 1, so the graph will be shifted up 1 unit.

<u>Thus, the answer is the last answer choice.</u>

<u></u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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