880, theres no change in between, only after every 13 years
Y - y1 = m(x-x1)
y - 7 = -3/2(x + 6)
The answer is 3.14 m
The area (A) of the circle with radius r is: A = π · r²
The area of the quarter of the circle is: A1 = 1/4A = 1/4 · π · r²
We have:
A1 = ?
r = ?
π = 3.14
d = 4 m
A diameter d is the twice of the radius r: d = 2r.
Therefore, the radius is the half of the diameter: r = d/2
So, the area of the quarter circle would be:
A1 = 1/4 · π · r² = 1/4 · π · (d/2)² =1/4 · π · d²/2² = 1/4 · π · d²/4 = 1/16 · π · d²
A1 = 1/16 · π · d² = 1/16 · 3.14 · 4² = 1/16 · 3.14 · 16 = 3.14 m
Answer:
13 units
Step-by-step explanation:
(x₁,y₁) = (-5 , 3) & (x₂ , y₂) = (7 ,8)
![= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%287-%5B-5%5D%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B%287%2B5%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%20%5Csqrt%7B%2812%29%5E%7B2%7D%2B%285%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B25%7D%5C%5C%5C%5C%3D%5Csqrt%7B169%7D%5C%5C%5C%5C%3D%2013)
Answer:
Step-by-step explanation:
4x^2 + 4x + 8 - 2x - 1 = 4x^2 + 2x + 7
