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3 years ago

The area of a triangle is 24 square inches. What is the height of the triangle if the base length is 4 inches?

Mathematics

2 answers:

Verizon [17]3 years ago

8 0

Answer:

area of the triangle= 1/2 × base × height

24 = 1/2 × 4 × height

height. = 24/2

= 12 inches

answer is third option

LiRa [457]3 years ago

4 0

12 inches third option

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Maya reads that 0.63 of Oak School is female and 0.47 of Elm School is female. She says that Oak School must have more females.

-BARSIC- [3]

Answer:

No not correct

Step-by-step explanation:

We are given information that Maya came to know that 0.63 pf Pal school is female and 0.47 of Elm school is female.

Without knowing the total number of students in each school, we cannot conclude that 0.63 is greater than 0.47

For example, say number of students in Oak school be 100, and in Elm school be 200

Females in Oak school = 0.63(100) =63

Females in Elm school = 0.47(200) = 94

We find that there are more females in Elm school

So with the information given, we cannot conclude she is correct , there are chances for her being wrong also.

4 0

3 years ago

The cost of in-state tuition at the University of Florida is $6,380 and is increasing at a rate of 3.1% per year. Write and use

olga_2 [115]

Answer:

loser

Step-by-step explanation:

8 0

3 years ago

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

Calculate the slope between (-12, 4) and (-14, 3).

Alika [10]

Answer:

1/2

Step-by-step explanation:

3-4 -1 1

----------- = ---------- = ---

-14-(-12) -2 2

8 0

3 years ago

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Write the equation of a line that is parallel to y = --x + 7 and that passes through the point (-4,1).

nordsb [41]

Answer:

slope: -1

y - 1= -(x + 4)

y - 1 = -x - 4

y = -x - 3

6 0

3 years ago

Read 2 more answers