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BartSMP [9]
3 years ago
13

How many times bigger is a group of 20 coins thn a group of 4 coins

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

5 times bigger

Step-by-step explanation:

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Find the equation of the line . Write in slope intercept form and in standard form. (SHOW YOUR SOLUTION)
AlladinOne [14]

Answer:

1) The slope-intercept and standard forms are y = -5\cdot x + 1 and 5\cdot x +y = 1, respectively.

2) The slope-intercept form of the line is y = \frac{5}{2}\cdot x -\frac{9}{2}. The standard form of the line is -5\cdot x +2\cdot y = -9.

3) The slope-intercept form of the line is y = \frac{5}{2}\cdot x + 5. The standard form of the line is -5\cdot x +2\cdot y = 10.

4) The slope-intercept and standard forms of the family of lines are y = \frac{2}{7}\cdot x -\frac{c}{7} and 2\cdot x -7\cdot y = c, \forall \,c \in \mathbb{R}, respectively.

5) The slope-intercept form of the line is y = 2\cdot x-7. The standard form of the line is -2\cdot x +y = -7.

Step-by-step explanation:

From Analytical Geometry we know that the slope-intercept form of the line is represented by:

y = m\cdot x + b (1)

Where:

x - Independent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

y - Dependent variable, dimensionless.

In addition, the standard form of the line is represented by the following model:

a\cdot x + b \cdot y = c (2)

Where a, b are constant coefficients, dimensionless.

Now we process to resolve each problem:

1) If we know that  m = -5 and b = 1, then we know that the slope-intercept form of the line is:

y = -5\cdot x + 1 (3)

And the standard form is found after some algebraic handling:

5\cdot x +y = 1 (4)

The slope-intercept and standard forms are y = -5\cdot x + 1 and 5\cdot x +y = 1, respectively.

2) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that (x_{1},y_{1})=(1,-2) and (x_{2},y_{2}) = (3,3), then we construct the following system of linear equations:

m+b= -2 (5)

3\cdot m +b = 3 (6)

The solution of the system is:

m = \frac{5}{2}, b = -\frac{9}{2}

The slope-intercept form of the line is y = \frac{5}{2}\cdot x -\frac{9}{2}.

And the standard form is found after some algebraic handling:

-\frac{5}{2}\cdot x +y = -\frac{9}{2}

-5\cdot x +2\cdot y = -9 (7)

The standard form of the line is -5\cdot x +2\cdot y = -9.

3) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that (x_{1},y_{1})=(-2,0) and (x_{2},y_{2}) = (0,5), then we construct the following system of linear equations:

-2\cdot m +b = 0 (8)

b = 5 (9)

The solution of the system is:

m =\frac{5}{2}, b = 5

The slope-intercept form of the line is y = \frac{5}{2}\cdot x + 5.

And the standard form is found after some algebraic handling:

-\frac{5}{2}\cdot x+y =5

-5\cdot x +2\cdot y = 10 (10)

The standard form of the line is -5\cdot x +2\cdot y = 10.

4) If we know that a = 2 and b = -7, then the standard form of the family of lines is:

2\cdot x -7\cdot y = c, \forall \,c \in \mathbb{R}

And the standard form is found after some algebraic handling:

-7\cdot y = -2\cdot x +c

y = \frac{2}{7}\cdot x -\frac{c}{7}, \forall \,c\in\mathbb{R} (11)

The slope-intercept and standard forms of the family of lines are y = \frac{2}{7}\cdot x -\frac{c}{7} and 2\cdot x -7\cdot y = c, \forall \,c \in \mathbb{R}, respectively.

5) If we know that (x,y) = (3,-1) and m = 2, then the y-intercept of the line is:

3\cdot 2 + b = -1

b = -7

Then, the slope-intercept form of the line is y = 2\cdot x-7.

And the standard form is found after some algebraic handling:

-2\cdot x +y = -7 (12)

The standard form of the line is -2\cdot x +y = -7.

6 0
3 years ago
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