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Semenov [28]
3 years ago
13

Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a

nd traveled at an average rate of 496 mph. The second airplane left at 8:30 a.m. and traveled at an average rate of 558 mph. How many hours did it take the first plane to travel to the destination?
Let x represent the number of hours that the first plane traveled.
Enter an equation that can be used to solve this problem in the first box.
Solve for x and enter the number of hours in the second box.
Mathematics
1 answer:
liberstina [14]3 years ago
7 0
First plane: 496x
<span>Second plane:  558( x - 1/2) </span>

<span>Equation: 496x = 558( x - 1/2) </span>

<span>Solving  x = 9/2 ,  or  x = 4.5 hours.

Hope this helps.</span>
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In the question we're provided with an equation that is :

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