PLEASE HELP ME WITH THIS, DUE IN 30 MINUTES, 20 POINTS!!!!!!

You come home from Brian’s Orchard with a big brown bag of apples: 23 Granny Smiths, 14 Honey Crisp and 31 Red Delicious. What i

garik1379 [7]

Answer:

a. Probability of Pulling one of each = 0.03175

b. Probability of Pulling 4 Honey Crisp = 0.001797

Probability of 2 G.Smith = 0.1144

Probability of 1 Red Delicious = 0.4559

Step-by-step explanation:

Given

Granny Smiths = 23

Honey Crisp = 14

Red Delicious = 31

Required

- Probability of Pulling out one of each

- Probability of Pulling out 4 Honey Crisp; 2 Granny Smiths; 1 Red Delicious

First, the total number of apple needs to be calculated.

Total = Granny Smiths + Honey Crisp + Red Delicious

Total = 23 + 14 + 31

Total = 68

Probability of Pulling 1 of each

= P(Granny Smiths) and P(Henry Ford) and P(Red Delicious)

- Granny Smiths;

This is calculated by dividing number of Granny Smiths apples by total number of apples.

Probability = 23/68

Similarly,

Probability of Pulling Honey Crisp= Number of Honey Crisp divided by total

Probability = 14/68

Probability = 7/34

Probability of Pulling Red Delicious = Number of Red Delicious divided by total

Probability = 31/68

So, Probability of Pulling 1 of each = 23/68 * 7/34 * 31/68

Probability = 4991/157216

Probability = 0.03175

Probability of Pulling out 4 Honey Crisp;

= P(Honey) * P(Honey) * P(Honey) * P(Honey)

= (P(Honey))⁴

= (7/34)⁴

= 2401/1336336

= 0.001797

Probability of Pulling 2 Granny Smiths;

= P(Granny) * P(Granny)

= (P(Granny))²

= (23/68)²

= 529/4624

= 0.1144

Probability of 1 Red Delicious

= number of red delicious divided by total

= 31/68

= 0.4559

3 0

3 years ago

A painter leans a 15 ft ladder against a building. The base of the ladder is 6 ft from the building. To the nearest foot, how hi

stiv31 [10]

Using the Pythagoras theorem

15^2 = x^2 + h^2 where h = height of ladder on the nuiding

h^2 = 15^2 - 6^2 = 189

= 13.75 ft to nearest hundredth

3 0

3 years ago

Read 2 more answers

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

so

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

3x-2y=10 solving equations

Schach [20]

Answer:

Step-by-step explanation:

3x-2y= 100

3x= 10 +2y

x =(10+2y)/

8 0

1 year ago

You prepare 10 scoops of dog food for 5 dogs, and prepare 16 scoops of dog food for 8 dogs. What

Svetllana [295]

Answer:

<em>12 scoops of dog food are needed for 6 dogs,</em>

Step-by-step explanation:

<u>Proportions</u>

The number of scoops of dog foods and the number of dogs are proportional variables.

We are given that 10 scoops of dog foods are used for 5 dogs. This gives a proportion of 10/5=2 scoops per dog.

We also know that 16 scoops are used for 8 dogs. The proportion is also 16/8=2 scoops per dog.

Thus, the constant of proportionality is 2.

For 6 dogs, you need to prepare 2*6 = 12 scoops of dog food.

12 scoops of dog food are needed for 6 dogs,

3 0

3 years ago