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4 years ago

Please help! I'm in a hurry.

Mathematics

2 answers:

d1i1m1o1n [39]4 years ago

8 0

Answer:

Step-by-step explanation:

15 and 13 have the same angle because they are opposit each other on the intersection of both lines.

VikaD [51]4 years ago

5 0

Answer:

KNM

Step-by-step explanation:

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PLEASE HELP ME!!!!<br><br> (if you don’t know don’t answer)

Sergio039 [100]

Answer:

Here are my answers

hope this helps

Step-by-step explanation:

1. isosceles triangle

2. 3x + 15 = 90 x = 25

x + 25 = 90 x = 65

x + 55 = 90 x = 35

3. The size for DAB is 84

My reasoning is I went from one angle to another by subtracting 180 from my answers. For example angle 132 is supplementary to the missing angle next to it. I subtract 180 from 132 and get 48. That already solves the 2 equivalent angles in the triangle so I have 48+48+x = 180 because a full triangle equals 180. I get x = 84 then I do the same thing I did with angle 132. Angle 84 is supplementary to the missing angle next to it. I subtract 84 from 180 and get 96 then go diagonal from angle C (which is 96) to angle A. Those are supplementary so I subtract 96 from 180 and get 84.

3 0

3 years ago

What is the length of square root 18 to the nearest hundredth

Katena32 [7]

Answer:

4.24

Step-by-step explanation:

3 0

4 years ago

Solve the equation x/4+3=-6

charle [14.2K]

X/4 = -9

x/4 = -9/1

cross multiply

x = -36

3 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i

Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

The points are:

(-2, 3), (0, 1), (2, -1), (3, -2)

So the relation is:

R = {(-2, 3), (0, 1), (2, -1), (3, -2)}

The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

Arrange them in the set

The range = {-2, -1, 1, 3}

7 0

1 year ago