Question

ILL GIVE A BRAINLIEST TO WHO CAN SOLVE THIS HURRY I NEED IT TURNED IN IN 10 MINS similar to the others that have been answered but different numbers.
A billiard ball is struck by a cue. It travels 120 cm before ricocheting off a rail and traveling another 100 cm into a corner pocket. The angle between the path as the
ball approaches the rail and the path after it strikes the rail is 40 degrees. How far is
the corner pocket from where the cue initially struck the ball? Round your answer to the nearest centimeter.

Answer 1

Answer:

Using Law of Cosines

c^2 = a^2 + b^2 - 2 a b cos c

c^2 = 150^2 + 200^2 - 2(150)(200)cos 60 = ==== c = 180.2776 cm

Answer 2

The angle between incident and reflection is 45 degrees not 90 degrees, so we need to use the cosine rule:
 
a^2 = 100^2 + 120^2 - 2*100*120*cos(45°)   where a is the distance  between pocket and initial strike.
 
so a = sqrt(100^2 + 120^2 - 2*100*120*cos(45°))
 
a = 86 cm (to the nearest cm).

i hope this helps !