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solniwko [45]
3 years ago
8

Plz need help right away !

Chemistry
1 answer:
jeyben [28]3 years ago
4 0

Explanation:

1 mole = 6.02 x 10^23 atoms (Avogadro’s number)

Step 1) Determine how many grams of a substance are in the problem

Step 2) Find the amount of grams in 1 mole of the substance

3) Multiply step one by step two

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given both a nacl and a h2o molecule, explain what type of bond each compound is and justify your reasoning.
nasty-shy [4]

Answer:

NaCl= ionic bond.

H2O=covalent bond.

Explanation:

NaCl:

Happens between metal and non-metal. since metal needs to lose an electron to get a full outer shell of electrons, sodium (Na) loses one electron and has a full outer shell of electrons.

chlorine is a gas so it needs to gain electrons to have a full outer shell. since it is in group 7, it needs to gain 1 electron for a full outer shell of electrons.

the lost electron from sodium is given to chlorine. this creates ions (a charged particle) so it is Na+Cl-. this creates a strong electrostatic attraction between the elements and causes them to join together in a lattice form.

H2O:

Covalent bonds happens between 2 gases. they share an electron or 2, and the bonds are very strong.

since oxygen needs 2 molecules to form a full outer shell. hydrogen have 1 atom in outer shell so they share the electron with the oxygen atom.

I can't fully explain why this is for H2O, but I hope you understand it.

8 0
3 years ago
For water to become a mechanical weathering agent through ice wedging, it needs to go through a cycle of freezing and thawing.
Elina [12.6K]
The statement "<span>For water to become a mechanical weathering agent through ice wedging, it needs to go through a cycle of freezing and thawing." is true</span>
4 0
3 years ago
What is the answer for #11
miskamm [114]
Lake water is favorable to Prokaryotic cell.
7 0
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sveticcg [70]

Answer:

the answer is b

Explanation:

7 0
3 years ago
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans
Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of H_2SO_4 (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H_2SO_4(aq)? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of H_2SO_4(aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_1,M_2\text{ and }V_2  are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL

Putting values in above equation, we get:

2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M

0.044 M is the molarity of H_2SO_4(aq).

4 0
3 years ago
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