Mass of vaporized triethylamine : 2.606 g
<h3>Further explanation</h3>
Given
0.5 L triethylamine
P = 18.5 psi
T = 25 °C
Required
mass of vaporized triethylamine
Solution
Conversion :
P 18.5 psi = 1,26 atm
T = 25 +273 = 298 K
Ideal gas law :
PV=nRT
n = PV/RT
Input the value :
n = (1.26 atm x 0.5 L) /(0.08205 x 298)
n = 0.0258
MW triethylamine = 101 g/mol
Mass triethylamine :
= n x MW
= 0.0258 x 101 g/mol
= 2.606 g
Answer:
True
Explanation:
The gaseous state is characterized in that the cohesion forces are usually null, in which the particles have their maximum mobility. The particles tend to occupy all the available volume, so their shape and volume are variable. The gaseous state is a dispersed state of matter, which means that the molecules are separated by distances much larger than the diameter of the gas molecules.
Answer:
I hope this helps u out a bit its my own words
Explanation:
Plant cells use chloroplast as kind of an extra mitochondria in a plant cell. They work together, when a chloroplast gets food through photosynthesis the mitochondria breaks down that food and distributes it through the cell.
Answer:4.48483134×10 to the power of 19 m to the power of 2/s
Explanation:
You should work it out some and see
Answer:
1.8321 kg
Explanation:
The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is 
Also, 1 kg = 1000 g
So, mass of carbon = 500 g
The formula for the calculation of moles is shown below:
Molar mass of carbon = 12.0107 g/mol
Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles
Considering the reaction:
From the reaction,
1 mole of C react to form 1 mole of 
So,
41.6295 moles of C react to form 41.6295 moles of
Moles of = 41.6295 moles
Molar mass of = 44.01 g/mol
So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g
Also, 1g = 0.001 kg
<u>So, amount of released = 1.8321 kg</u>
