All categories

2 years ago

How to calculate work done with change in volume and pressure.

Chemistry

1 answer:

natali 33 [55]2 years ago

3 0

$W = \displaystyle \int dW = \displaystyle \int^{V_2}_{V_1} p ~dV = p(V_2 - V_1) = p \Delta V$

You might be interested in

Complete the following molecular models to represent balanced equations by

trasher [3.6K]

Answer:

I do not know the Answer I'm just trying to get my point

Explanation:

Thank you

7 0

2 years ago

Which set of coefficients will balance this chemical equation?

Katarina [22]

Answer:

B 1,3

Explanation:

Count the atoms on each side of the arrow, they have to be equal

After arrow

2x C

6x O

4x H

Before the arrow

2x C - correct, as it is the only compound with C then there must only be 1 mole of it.

This is also the correct amount of H

We need 6x O total so 6/2 = 3

So there are 3 moles of O

7 0

3 years ago

The chemical formula for glucose is C6H12O6. How many types of elements are found in glucose?

Tasya [4]

Answer:

Glucose has a chemical formula of:C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms. You will be building one type of sugar called glucose.

3 0

2 years ago

Read 2 more answers

Question 10 (4 points)

Alex17521 [72]

Chemical Bond

The forces that hold atoms make compounds and molecules

3 0

2 years ago

Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3

stealth61 [152]

This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

V₁ = 4.00 l
P₁ = 365 mmHg
T₁ = 20 °C + 273 = 293 K
V₂ = 2,80 l
T₂ = 30 °C + 273 = 303 K
P₂ = ¿?

We apply the following formula:

P₁V₁T₂=P₂V₂T₁ ⇒ General formula

Where:

P₁=Initial pressure
V₁=Initial volume
T₂=end temperature
P₂=end pressure
T₂=end temperature
V₁=Initial temperature

We clear for final pressure (P2)

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}$

We substitute our data into the formula:

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 } \end{gathered}$}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}$

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>

6 0

1 year ago