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3 years ago

Please help due ASAP Show workings

Mathematics

1 answer:

quester [9]3 years ago

7 0

Abcdefghijklmnopqrstuvwxyz not e you know your abc next time will you sing with me

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Pls help me im sooo stuck on math

Alla [95]

87

You can add up the angles that are labeled(73,110,and 90 because of the right angle) and get 273.

For a quadrilateral, all of the angles add up to 360.

So, subtract 360-273.

You get 87.

Hope this helps:)

8 0

3 years ago

A painter is painting a rectangular wall that measures 20.5 ft by 16.4 ft. Each gallon can of paint covers 200 square feet. What

alekssr [168]

The painter needs at least two gallons of paint to cover the wall.

To get this answer, you first need to find the area of the wall; by multiplying 20.5 x 16.4. This will get you 336.2.

Then, you need to divide 336.2 by 200. This will get you approx. 1.6.

If it's asking for partial gallons as well, stop here. Your answer is 1.6.

If not, continue.

Unless you're including partial gallons, you can't get 1.6 gallons of paint, so you need to round up. This will be 2 gallons.

5 0

2 years ago

Read 2 more answers

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

Working together, it takes Sam, Jenna, and Francisco two hours to paint one room. When Sam works alone, he can paint one room in

lutik1710 [3]

Answer: 12 hours

Step-by-step explanation:

Given : Working together, it takes Sam, Jenna, and Francisco two hours to paint one room.

When Sam works alone, he can paint one room in 6 hours. When Jenna works alone, she can paint one room in 4 hours.

Let 't' be the time taken by Francisco to paint one room on his own.

Then , we have

Rate of work of Sam +Rate of work of Jenna + Rate of work of Francisco =Rate of work they all do together

$\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{t}=\dfrac{1}{2}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{1}{6}+\dfrac{1}{4})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{4+6}{24})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{10}{24}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{6-5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{1}{12}$

i.e. t= 12

Hence, Francisco would take 12 hours to paint one room on his own.

8 0

3 years ago

What is 15 thousands 20 hundreds 5 ones=

Law Incorporation [45]

The answer is 152,005

4 0

4 years ago