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mario62 [17]
3 years ago
5

The number of students at Maria's school decreased by 98% of last year's number currently there are 1170 students how many stude

nts were there last year went to the nearest whole number
Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0
X=number of students at Marita's high school last year
98%=.98
.98x=1170
x=1170/.98
x=1194
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AysviL [449]

Answer: 79 easy do 14x5 then add 9 which equals 79

6 0
3 years ago
-2(x-5)=6(2- 1/2x)<br><br> Please show your work. Distributive property, remove variable
schepotkina [342]

The solution of given equation is x=2

Further explanation:

In order to solve the given equation we have to isolate the variable x on one side of the equation. The process will involve distributive property and simplification.

Given:

-2(x-5)=6(2-\frac{1}{2}x)\\Apply\ distributive\ property\\-2x-2(-5)=(6)(2)-(6)(\frac{1}{2}x)\\-2x+10=12-\frac{6}{2}x\\-2x+10=12-3x\\-2x+3x=12-10\\x=2

The solution of given equation is x=2

Keywords: Linear Equation, Distributive property

Learn more about linear equations at:

  • brainly.com/question/10169676
  • brainly.com/question/10208427

#LearnwithBrainly

6 0
4 years ago
a tank is 4÷5 full of water. after drawing off 190 litees of water,it is just 1÷6 full. what is the capacity of the tank​
soldier1979 [14.2K]

Hey there! I'm happy to help!

Let's have the capacity be c. The tank is currently at 4/5c. We subtract 190 and then we are at 1/6c. Let's set this up as an equation and solve it.

4/5c-190=1/6c

We want to get the c all by itself to see the capacity of the tank. Let's get all of the c values on the left side of the equation and the numbers on the right by using inverse operations.

4/5c-190=1/6c

Add 190 to both sides.

4/5c=1/6+190

Subtract 1/6 from both sides.

19/30c=190

Divide both sides by 19/30.

c=300

So, the capacity of the tank is 300 liters of water.

Have a wonderful day and keep on learning! :D

8 0
2 years ago
To
yanalaym [24]

Answer:

I think it's 56 students have a gadgets

5 0
2 years ago
Determine for what values of x and y are the following equalities always true.
Agata [3.3K]
(k+1)x-(2k+3)y-3k-5=0
kx + x - 2ky - 3y - 3k - 5 = 0
(x - 2y) k + (x - 3y) = 3k + 5

therefore
x - 2y = 3
x - 3y = 5

Subtract 2 equations
y = -2
x = -1
3 0
3 years ago
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