Well, first, find-out how fast he was going the first time, by dividing 310 by 5. This gives you 62 mph. Now, divide 403 miles by 62 miles per hour in order to find-out how long it would take him to drive 403 miles, if he is constantly doing 62 mph. Your final answer is six-and-a-half hours.
Answer:
Length = 18.099 ft
Width = 11.049 ft
Step-by-step explanation:
let the length of the field be x ft
and the width be y ft
as per the condition given in problem
x=2y-4 -----------(A)
Also the area is given as 200 sqft
Hence
xy=200
Hence from A we get
y(2y-4)=200
taking 2 as GCF out
2y(y-2)=200
Dividing both sides by 2 we get


subtracting 100 from both sides

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

Here in our case
a=1
b=-1
c=-100
Putting those values in the formula and solving them for y


Solving first





Solving second one






Which is wrong as the width can not be in negative
Our width of the field is
y=11.099
Hence the length will be
x=2y-4
x=2(11.049)-4
x=22.099-4
x=18.099
Hence our length x and width y :
Length = 18.099 ft
Width = 11.049 ft
Of means multiply
24*5/8=15
15 students earned an A