Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Answer:
Step-by-step explanation:
y - 6 = 4(1 - 4)
y - 6 = 4 - 16
y - 6 = -12
y = -12 + 6
y = -6
This is a horizontal line through the point (0, -6). See below.
2 rooms would be 62+42 which is 104
3 rooms would be 104+42 which is 146
4 rooms would be 146+42 which is 188
5 rooms would be 188+42 which is 230
6 rooms would be 230+42 which is 272
but these are the prices including the 20$
without the 20$ the prices would be
2 rooms is 84
3 rooms is 126
4 rooms is 168
5 rooms is 210
6 rooms is 252