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kondor19780726 [428]
3 years ago
10

To rent a certain meeting room, a college charges a reservation fee of $47 and an additional fee of $5.40 per hour. the film clu

b wants to spend less than $74.00 on renting the meeting room. what are the possible amounts of time for which they could rent the meeting room? use t for the number of hours the meeting room is rented, and solve your inequality for t .
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
+ <span>use t for the number of hours the meeting room is rented
</span>+ <span>college charges a reservation fee of $47 and an additional fee of $5.40 per hour.So we have 47+ 5.40t
+ and </span>the film club wants to spend less than $74.00 on renting the meeting room.So we need 47+ 5.40t<74
or 5.40t< 74-47
and 5.40t<27 we have t< 27:5.40=5
So <span>the possible amounts of time for which they could rent the meeting room less than 5 hours</span>
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It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportat
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Answer:

State the null and alternative hypotheses.  

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Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

Step-by-step explanation:

Data given and notation  

\bar X=114 represent the sample mean  

\sigma=22 represent the population standard deviation

n=36 sample size  

\mu_o =120 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part 1

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

If we analyze the size for the sample is > 30 and we  know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

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