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kozerog [31]
3 years ago
12

The graph of which function is decreasing over the interval (–4, ∞)?

Mathematics
2 answers:
insens350 [35]3 years ago
7 0

This can be solved by the method of elimination.

We have been given that the function should decrease over (-4,∞)

So, since its between -4 and ∞ , we can eliminate option A and C. This is because options A and C are actually increasing over (-4,∞) and not decreasing.

So, this leaves us with options B and D. Next we find the vertex of the two functions. The vertex of Option B, that is -(x+4)^2 +4 lies at the point (-4,4) and decreases with x over the interval (-4,∞).

Whereas the option D, -(x-4)^2+4 has the vertex at (4,4) and hence the interval is not between -4 and infinite.

Hence Option B, -(x+4)^2 +4 is the answer asthe function is decreasing over the interval (–4, ∞)

padilas [110]3 years ago
3 0
I think second must b the answee
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Please help! Thanks! Show work!
geniusboy [140]
Answer: The toy should be 2.4 inches tall

------------------------------------
------------------------------------

Explanation:

First convert 6 ft to inches
6 ft = (6 ft)*(12 in/1 ft) = (6*12) inches = 72 inches

So, 6 ft = 72 inches

The toy is manufactured with a scale of 1:30 meaning that the toy is 1 unit tall compared to the soldier which is 30 units tall. The soldier is 30 times taller than the toy. We can therefore form the ratio

1/30 = x/72

where x is the height of the toy soldier in inches

Cross multiply and solve for x

1/30 = x/72
1*72 = 30*x
72 = 30*x
72/30 = 30*x/30
72/30 = x
x = 72/30
x = 12/5
x = 2.4

So the toy should be 2.4 inches tall.

Note how 30 times 2.4 gives us
30*2.4 = 72
which fits with the theme that the real soldier is 30 times taller than the toy counter part.


3 0
3 years ago
how many servings are in a bag of trail mix that weighs 11 1/2 ounces and each serving of trail miix weighs 3/4 ounces
Mariulka [41]

let's firstly convert the mixed fraction to improper fraction, and then divide.

\bf \stackrel{mixed}{11\frac{1}{2}}\implies \cfrac{11\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{23}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{23}{2}\div \cfrac{3}{4}\implies \cfrac{23}{2}\cdot \cfrac{4}{3}\implies \cfrac{23}{3}\cdot \cfrac{4}{2}\implies \cfrac{23}{3}\cdot 2\implies \cfrac{46}{3}\implies 15\frac{1}{3}

8 0
3 years ago
Can anyone help me with my math homework! My teacher didn't even discuss it! I would appreciate it! Thank you!
Hatshy [7]
Please, in the future, post just one problem at a time.

Looking at Problem #1:  The line intersects the y-axis at (0,-3) and intersects the x-axis at (1,-1).  At least, this is what I see; your graph is small.
                                                                           -3-[-1]
The slope of that line is then  m = rise / run = ------------ = +2.
                                                                            0 - 1
                                       [change in y]
Slope = m = rise / run = --------------------
                                        [change in x]
8 0
3 years ago
You lose one quarter, two dimes, and two nickels.
torisob [31]

are you sure this is full question?

7 0
3 years ago
Read 2 more answers
Calculate the slope of the line that contains the points (-2, -4) and (2, 4).
liubo4ka [24]

Answer:

Slope is 2

Step-by-step explanation:

(-2, -4) and (2, 4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4+4)/(2+2)

m=8/4

m = 2

6 0
3 years ago
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