The boundaries:
x = 0, y = 8; y = 0, √x³ = = 8, x = 4


= π ( 64 x - 16 * 2 *√x^5 + x^4 / 4 ) =
= π ( 320 - 1024/5 + 64 ) =
179.2 π
Answer:
13. 10
14. 51
Step-by-step explanation:
it is the same denominator therefore only the numerators are added and the sign is maintained. The answer is -12/9 but it can be reduced to -4/3.
The answer is C because you just turn it upside down