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2 years ago

14

Y plus 4 plus 3(y plus 2)

2 answers:

Serga [27]2 years ago

5 0

Answer:

5y+11

Step-by-step explanation:

y+3+4(y+2)

Use the distributive property to multiply 4 by y+2.

y+3+4y+8

Combine y and 4y to get 5y.

5y+3+8

Add 3 and 8 to get 11.

Iteru [2.4K]2 years ago

5 0

2(2y+5)

Hope this helps! :)

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2 years ago

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Cora babysat for 3 1/2 hours and charged at $28. At the same hourly rate, what would she charge for 5 1/2 hours of babysitting?

RUDIKE [14]

42.9 goodluck :) ...

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3 years ago

What is the value of -2/5 ÷ 3/4

ale4655 [162]

-8/15 hope it helps!

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3 years ago

Solve For Each Variable.

bixtya [17]

The first equation given $6=1-2n+5$

We have to add 1 and 5 to the right side first. We will get,

$6= 6 - 2n$

To get rid of 6 from the right side we have to subtract 6 from both sides.

$6-6 = 6-6-2n$

$6-6 = -2n$

$0=-2n$

To find n we have to move -2 to the other side by dividing both side by -2.

$0/-2 = -2n/-2$

$0= n$

$n=0$

So we have got the required answer for the first question.

The solution is n = 0.

The second equation given,

$8x-2 = -9+7x$

First we have to move 7x to the left side by subtracting it from both sides.

$8x-7x-2 = -9+7x-7x$

$8x-7x-2 = -9$

$x-2 = -9$

Now we have to move -2 to the right side by adding 2 to both sides.

$x-2+2 = -9+2$

$x = -9+2$

$x = -7$

We have got the required answer for the second question.

The solution is x = -7.

The third equation given,

$-8 = -(x+4)$

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

$8=x+4$

Now we have to move 4 to left side by subtracting it from both sides.

$8-4 = x+4-4$

$8-4 = x$

$4=x$

$x = 4$

So we have got the required answer .

The solution is x = 4.

3 0

2 years ago

Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha

GalinKa [24]

Answer:

$\theta_1 \ n\ \theta_2 = 120, 240$

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

$Nonagon = 9\ sides$

$Hexagon = 6\ sides$

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

$\theta = \frac{360}{9} =40$

List the multiples of 40

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

<u>Hexagon</u>

$\theta = \frac{360}{6} =60$

List the multiples of 60

$\theta_2 = 60, 120, 180, 240, 300$

List out the common angles

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

$\theta_2 = 60, 120, 180, 240, 300$

$\theta_1 \ n\ \theta_2 = 120, 240$

This means that, only a rotation of $120, 240$ will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

7 0

2 years ago