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MissTica
3 years ago
14

Please Help Me With This So I can understand how to do it.

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
Idjskabsidndowkahsowhwhebeiwnqjdidbeid
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which expressions represents a 20% discount off the price of an item that originally cost D dollars ​
Charra [1.4K]

Answer:

D - (D/5)

Step-by-step explanation:

Let's imagine that D equals 100 dollars -

Well, we know that to get 20% of an amount, we need to divide the amount by five. So let's do that -

100 / 5 = 20

We now know that 20% of 100 dollars is equal to 20 dollars. We have now finished the first part. On to the second part.

We now need to take away 20% of 100 dollars off of 100 dollars - this is the price of the item after the discount.

100 - 20 = 80 dollars.

We now fit in D instead of 100 dollars -

D - (D/5)

6 0
3 years ago
Read 2 more answers
Need help with compound fractions. Please answer both
Reika [66]
\frac{8*( \frac{c}{c} )- \frac{3}{c} }{2*( \frac{7c}{7c})+ \frac{3}{7c}  }  \\  \\  \frac{ \frac{8c-3}{c} }{ \frac{14c+3}{7c} }  \\  \\  \frac{8c-3}{c} * \frac{7c}{14c+3}  \\  \\ =  \frac{56c-21}{14c+3}

Domain restrictions are what x values make the denominator zero.
a² + 5a - 36 = (a + 9)(a - 4)
a ≠ -9 ; a ≠ 4
6 0
3 years ago
Darla drives at a constant speed of 45 miles per hour. If she drives for y miles and it takes her x hours, write the two-variabl
Darya [45]

Answer:

y = 45x miles

Step-by-step explanation:

Speed is the rate of change of distance with time. Mathematically,

speed = distance/time

Given that Darla travels at a constant speed of 45 miles per hour and for y miles, it takes her x hours then

45 = y/x

multiply both sides by x

45x = y

then the number of miles (y) Darla can drive in x hours

y = 45x (in miles)

7 0
3 years ago
2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1​
Misha Larkins [42]

\\ \sf\longmapsto L-M

  • Put values

\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]

Just substract corresponding terms

\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]

Option B

6 0
3 years ago
Help i gotta get it turned in soon​
Katen [24]

Answer: Ill be glad to help but i need a better picture of the whole thing

Step-by-step explanation:

4 0
3 years ago
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