Answer:
Choice 1
Step-by-step explanation:
m^2 +n^2=13^2
m^2=13^2-n^2
n^2=13^2-m^2
Both m & n =(13 x sq rt 2)/2
To put it another way:
m=(sq rt 2)/2 x 13
n=(sq rt 2)/2 x 13
Answer: 48
Step-by-step explanation: there is 4 cups in a quart
Answer:
2x squared +1 (-)x squared -7 is
a.) x squared +8
Step-by-step explanation:
:)
An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric