-98-31 can also be written as
(-98) + (-31)
We know 98+31=129
Therefore -129
Answer:
![22 > x > 10](https://tex.z-dn.net/?f=22%20%3E%20x%20%3E%2010)
![10 < x < 22](https://tex.z-dn.net/?f=10%20%3C%20x%20%3C%2022)
Step-by-step explanation:
Given
![Side\ 1 = 6](https://tex.z-dn.net/?f=Side%5C%201%20%3D%206)
![Side\ 2 = 16](https://tex.z-dn.net/?f=Side%5C%202%20%3D%2016)
Required
Determine the inequality that represents the third side
Represent the third side with x.
For the triangle to be true, two of the following condition must be true.
![6 + 16 > x](https://tex.z-dn.net/?f=6%20%2B%2016%20%3E%20x)
![6 + x > 16](https://tex.z-dn.net/?f=6%20%2B%20x%20%3E%2016)
![16 + x > 6](https://tex.z-dn.net/?f=16%20%2B%20x%20%3E%206)
![6 + 16 > x](https://tex.z-dn.net/?f=6%20%2B%2016%20%3E%20x)
-- True
![6 + x > 16](https://tex.z-dn.net/?f=6%20%2B%20x%20%3E%2016)
![x > 16 - 6](https://tex.z-dn.net/?f=x%20%3E%2016%20-%206)
-- True
![16 + x > 6](https://tex.z-dn.net/?f=16%20%2B%20x%20%3E%206)
![x > 6 - 16](https://tex.z-dn.net/?f=x%20%3E%206%20-%2016)
--- False; Because, x can't be negative.
So, we have:
and ![x > 10](https://tex.z-dn.net/?f=x%20%3E%2010)
This can be combined to give:
![22 > x > 10](https://tex.z-dn.net/?f=22%20%3E%20x%20%3E%2010)
or
![10 < x < 22](https://tex.z-dn.net/?f=10%20%3C%20x%20%3C%2022)
Your answer will be D.
So, you have the angles 12, 9, 6, and 3. You may see that the place that 6 is makes this a non perfect square. When you have this problem simply add the number on top of it with the number that makes this problem.
For instance...
![\boxed{6+3=9}](https://tex.z-dn.net/?f=%5Cboxed%7B6%2B3%3D9%7D)
So, when finding area you must multiply the 2 lengths with each other.
So here our bottom length is also 12. Thus, we must multiply 9 and 12 together.
For instance...
![\boxed{9*12=108}](https://tex.z-dn.net/?f=%5Cboxed%7B9%2A12%3D108%7D)
The answer is y<3. Hope this helps. (correct me if im wrong and sorry for the bad handwriting)