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4 years ago

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the basketball team is going to madison square garden to see a knicks game. there are 39 children on the team. they can fit 9 ch

ildren in a bus. how many buses does the team need?

2 answers:

Goshia [24]4 years ago

8 0

5 because you would need to round up

juin [17]4 years ago

4 0

5 would be the answer

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CAN SOMEONE PLS HELP ME WITH THIS. YOU'LL EARN 50 POINTS!!!

Morgarella [4.7K]

Answer:

a. x is the width of the fence in feet and y is the length of the fence in feet , f = 2x+ 2y equation represents that the fence is twice the width and twice the length , x>10 represents that the width should be atleast 10 feet , y >8 represents that the length should be at least 8 feet , 3f<120 represents the cost constraint. it says that the fencing cost $3 per foot and should cost less than or equal to 120 . b. yes, i agree. this is because the inequality f>0 implies that the length of the fencing should be greater than 0. I hope this helps ! :)

7 0

3 years ago

A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia

Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and irrespective of the order.

${n\choose k}=\frac{n!}{k!(n-k)!}$

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

$^{n}P_{k}=\frac{n!}{(n-k)!}$

In this case we need to select two different cards from a pack of 52 cards.

Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${52\choose 2}=\frac{52!}{2!(52-2)!}$

$=\frac{52\times 51\times 50!}{2!\times50!}\\=1326$

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

$^{n}P_{k}=\frac{n!}{(n-k)!}$

$^{52}P_{2}=\frac{52!}{(52-2)!}$

$=\frac{52\times 51\times 52!}{50!}$

$=52\times 51\\=2652$

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0

3 years ago

There are 2,250 benches in a city. The number of red benches is 350 more than the number of blue benches. How many red benches a

Mrac [35]

2,250-350=1900

1900÷2=950

red: 950+350= 1300

blue: 950

<u>Answer:</u>

1300 red benches

950 blue benches

<u>Proof:</u>

1300+950= 2250

7 0

4 years ago

Read 2 more answers

(x-81/10)> (68-81/10) and (x-81/10)<(68-81/10)

Fofino [41]

Answer:

what you need should be testing for u

6 0

3 years ago

There are different types of correlation one can use based on the types of variables being examined. When conducting an analysis

JulijaS [17]

The correct option is A.

When the data are nominal or ordinal.

<h3>What are the Types of correlation?</h3>

There are three types of correlation:

1. Positive and negative correlation

2. Linear and non-linear correlation

3. Simple, multiple, and partial correlation

<h3>According to the information:</h3>

There are different types of correlation one can use based on the types of variables being examined.

Spearman’s rho is a superb choice when you have nominal or ordinal data because Pearson’s isn't appropriate. Ordinal data have a minimum of three categories and the categories have a natural order. for instance , first, second, and third during a race are ordinal data.

<h3>Briefing:</h3>

Two variables can have some quite relationship, i.e., change in one may cause a change within the other.

If a change within the value of one variable causes a simultaneous change in the other variable in the same or opposite direction, then it’s termed as correlation, or these variables are said to be correlated. Keeping these in mind the answer to this question is When the data are nominal or ordinal

When the data are nominal or ordinal.

So the option no A is correct.

To know more about correlation visit:

brainly.com/question/28165535

#SPJ4

I understand that the question you are looking for is:

There are different types of correlation one can use based on the types of variables being examined. When conducting an analysis, when do you need to use spearman’s rho instead of Pearson's r ?

A. When the data are nominal or ordinal.

B. When the data are ratio or interval.

C. When the data are random.

D. Spearman's rho should never be used for correlations.

7 0

1 year ago