Find the value of x in the triangle shown below. х 53° 2 97°

Mathematics

1 answer:

tino4ka555 [31]2 years ago

5 0

Given:

Consider the below figure attached with this question.

To find:

The value of x.

Solution:

Angle sum property of a triangle: According to this property, the sum of all interior angles of a triangle is 180 degrees.

Using the angle sum property of triangle, we get

$x^\circ+53^\circ+97^\circ=180^\circ$

$x^\circ+150^\circ=180^\circ$

$x^\circ=180^\circ-150^\circ$

$x^\circ=30^\circ$

Therefore, the value of <em>x</em> is 30 degrees.

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From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Which of the following is equivalent to -9-√-36

LenKa [72]

Answer:

The answer to your question is: -9 - 6i

Step-by-step explanation:

Process

$\sqrt{-36} = \sqrt{(-1)(36)} = \sqrt{-1} \sqrt{36} = (6i)$