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4 years ago

8

On a test, Andre gets 4 times as many answers correct as he gets wrong. Write the ratio of questions he gets correct to the tota

l number of questions.

2 answers:

STALIN [3.7K]4 years ago

5 0

Answer:

4:5

Step-by-step explanation:

NemiM [27]4 years ago

3 0

I think it's 1:4 since if he gets two wrong than two times four is eight .

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3 years ago

Find all complex solutions of 7x^2-7x+3=0

Sedaia [141]

Answer:

The complex solutions are

$x = (\frac{7-\sqrt{35} i }{42} , ) x = \frac{7 + \sqrt{35} i }{42})$

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation 7 x² - 7 x +3=0

$x = (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} , \frac{-b +\sqrt{b^{2}-4ac } }{2ac})$

Given standard equation

a x² +b x +c =0

a = 7 , b= -7 and c=3

<u><em>Step(ii):-</em></u>

<u><em></em></u> $x = (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} , \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})$ <u><em></em></u>

<u><em></em></u> $x = (\frac{7-\sqrt{(49-84 } }{42} , \frac{7 +\sqrt{(49-84 } }{42})$ <u><em></em></u>

$x = (\frac{7-\sqrt{35i^{2} } }{42} , \frac{7 + \sqrt{35i^{2} } }{42})$

$x = (\frac{7-\sqrt{35} i }{42} , \frac{7 + \sqrt{35} i }{42})$

<u><em></em></u>

8 0

3 years ago

5x = 35<br> full answer pls show your work

cupoosta [38]

5x=35
x=35/5 (/=divided)
x= 7

so you divide 5x by 5 to cancel out that 5 and then since you did it to that side you have to do it to the other side so you divide 35 by 5 and that equals 7 so you’re left with x=7

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3 years ago

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