Plug in 10/3
9(10/3)-19= 3(10/3)+1
30-19= 10+1
11=11
That is the solution.
I hope this helps!
~kaikers
Answer:
x = √39
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Identify</u>
Leg <em>a</em> = <em>x</em>
Leg <em>b</em> = 5
Hypotenuse <em>c</em> = 8
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: x² + 5² = 8²
- Isolate <em>x</em> term: x² = 8² - 5²
- Exponents: x² = 64 - 25
- Subtract: x² = 39
- Isolate <em>x</em>: x = √39
Answer:
C
Step-by-step explanation:
Hope this is right, this is what I got.
Answer:
B: (4x - 7)(16x^2 + 28x + 49)
Step-by-step explanation:
64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3. This is the difference of two cubes. The appropriate formula for factoring such is
a^3 - b^3 = (a - b)(a^2 + ab + b^2). Therefore,
our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49). This is Answer B.
Answer:
87.92
Step-by-step explanation:
3.14(a²+ab)=
<em>Plugging in values for a and b</em>
3.14(4²+4×3)=
3.14(16+12)=
3.14(28)=
87.92
