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kkurt [141]
3 years ago
8

A line through (2, 15) and (6, 7)​

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

y = -2x + 19

Step-by-step explanation:

Let the equation of the line is y = mx + b

Here, m = slope of the line

          b = y - intercept

slope of a line passing through (x₁, y₁) and (x₂, y₂) is given by

m=\frac{y_2-y_1}{x_2-x_1}

slope of line passing through (2, 15) and (6, 7) will be

m=\frac{15-7}{2-6}

    = (-2)

Equation of the line will be,

   y = -2x + b

Since line passes through point (2, 15)

15 = -2 (2) + b

b = 15 + 4

b = 19

Therefore, equation will be,

y = -2x + 19

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arsen [322]

Answer/Step-by-step explanation:

Given:

m<EFH = (5x + 1)°

m<HFG = 62°

m<EFG = (18x + 11)°

Required:

1. Value of x

2. m<EFH

3. m<EFG

SOLUTION:

1. Value of x

m<EFH + m<HFG = m<EFG (angle addition postulate)

(5x + 1) + 62 = (18x + 11)

Solve for x using this equation

5x + 1 + 62 = 18x + 11

5x + 63 = 18x + 11

Subtract 18x from both sides

5x + 63 - 18x = 18x + 11 - 18x

-13x + 63 = 11

Subtract 63 from both sides

-13x + 63 - 63 = 11 - 63

-13x = -52

Divide both sides by -13

-13x/-13 = -52/-13

x = 4

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Plug in the value of x

m<EFH = 5(4) + 1 = 20 + 1 = 21°

3. m<EFG = 18x + 11

m<EFG = 18(4) + 11 = 72 + 11 = 83°

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