A line through (2, 15) and (6, 7)
1 answer:
Answer:
y = -2x + 19
Step-by-step explanation:
Let the equation of the line is y = mx + b
Here, m = slope of the line
b = y - intercept
slope of a line passing through (x₁, y₁) and (x₂, y₂) is given by
slope of line passing through (2, 15) and (6, 7) will be
= (-2)
Equation of the line will be,
y = -2x + b
Since line passes through point (2, 15)
15 = -2 (2) + b
b = 15 + 4
b = 19
Therefore, equation will be,
y = -2x + 19
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Solution/Answer : 4
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)
Solution: the first you do is multiply the last two parentheses to get -10xy
Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y
The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)
Hopes this helps :)
Answer:
Option C -M'K' is the same length as MK
Step-by-step explanation:
Given : Line segment MK has endpoints at (2, 3) and (5,4)
M'K' is the reflection of MK over the y-axis
By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)
which implies M'K' has end points (-2,3) and (-5,4)
Now, we find the length of MK
let
⇒
⇒
⇒ ....(1)
Now, we find the length of M'K'
let
⇒
⇒
⇒ .....(2)
from (1) and (2) we simply show that the length of MK and M'K' is equal
we can also refer the figure attached for reflection of MK and M'K'
therefore, Option C is correct
