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3 years ago

Your friend finds the value of 8⁴. 8⁴ = 8x4 = 32 Is your friend correct? Explain

1 answer:

4 0

I would say my friend is correct. I think this because when doing function tables, i would often say x2, x5, etc. This would mean that it would be X x 2, and X x 5. If you replace the "x" and turn it into 8, than I would think it would mean the same thing. So, yes. My friend is correct.

I'm not sure if this was what you were looking for, but I hope this helps somehow!

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If g(x)=8x+1, what is g

gizmo_the_mogwai [7]

Shauiaiaiaiwiwbrjfoficidhdj

3 0

3 years ago

What is the answer to these question?

Natali5045456 [20]

Answer:

2. y = 7/2 x -2

3. y = 3/4x-1

Step-by-step explanation:

points (0,-2) (4,12)

slope = (y2-y1)/(x2-x1)

slope = (12--2)/(4-0)

= (12+2)/4

= 14/4 = 7/2

the slope is 7/2 and the y intercept is -2

y = mx+b

y = 7/2 x -2

points (0,-1) (4,2)

slope = (y2-y1)/(x2-x1)

slope = (2--1)/(4-0)

= (2+1)/4

= 3/4

the slope is 3/4 and the y intercept is -1

y = mx+b

y = 3/4x-1

3 0

3 years ago

Suzy earns $7.50 per hour. She worked 32.5 hours last week. What was the amount of her check?

jekas [21]

You would have to do
7.50 x 32.5 which would equal

243.75

Please mark brainlist if helped! c:

8 0

3 years ago

Read 2 more answers

Let F = (2, 3). Find coordinates for three points that are equidistant from F and the y-axis. Write an equation that says P = (x

True [87]

Answer:

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

Step-by-step explanation:

Let $F(x,y) = (2,3)$ and $R(x,y) =(0, y')$ , where $P(x,y)$ is a point that is equidistant from F and the y-axis. The following vectorial expression must be satisfied to get the location of that point:

$F(x,y)-P(x,y) = P(x,y)-R(x,y)$

$2\cdot P(x,y) = F(x,y)+R(x,y)$

$P(x,y) = \frac{1}{2}\cdot F(x,y)+\frac{1}{2} \cdot R(x,y)$ (1)

If we know that $F(x,y) = (2,3)$ and $R(x,y) = (0,y')$ , then the resulting vectorial equation is:

$P(x,y) = \left(1,\frac{3}{2} \right)+\left(0, \frac{y'}{2}\right)$

$P(x,y) =\left(1,\frac{3+y'}{2} \right)$

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

If we know that $y_{1}' = -3$ , $y_{2}' = 0$ and $y_{3}' = 3$ , then the coordinates for three points that are equidistant from F and the y-axis:

$P_{1}(x,y) = \left(1,\frac{3+y_{1}'}{2} \right)$

$P_{1}(x,y) = (1,0)$

$P_{2}(x,y) = \left(1,\frac{3+y_{2}'}{2} \right)$

$P_{2}(x,y) = \left(1,\frac{3}{2} \right)$

$P_{3}(x,y) = \left(1,\frac{3+y_{3}'}{2} \right)$

$P_{3}(x,y) = \left(1,6 \right)$

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

7 0

3 years ago

What if I had a number bond that says

notka56 [123]

Well, I believe that it's letting you know $\frac{2}{7}$ is simply just a fraction of a full number {1}

For example, You have a pie. Your Mother cut it in 7 slices, if your family ate 5 of the seven slices, there would be how many slices left?
The would be $\frac{2}{7}$ of one whole pie.

So, I hope you find this helpful. :3

7 0

4 years ago