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Lunna [17]
3 years ago
7

4, 2, 1, 2, ... O Arithmetic O Geometric O Neither

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

Step-by-step explanation:

Neither...there is no common difference nor a cmon ratio do neither

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1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

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3 years ago
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You must add 15 liters of pure water
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1/(cot^2 (x)) - 1/(cos^2 (x))
Airida [17]

Step-by-step explanation:

1 is your answer its law of trig identises

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Answer:

$80

Step-by-step explanation:

$5 per hour, then for 16houurs. 5*16=80

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A: 292892 b: 2972 c: 9272726: d: 196373
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