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marta [7]
3 years ago
12

A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is

the number of 3-point questions and y is the number of 5-point questions, the system shown represents this situation. x + y = 24 3x + 5y = 100 What does the solution of this system indicate about the questions on the test? The test contains 4 three-point questions and 20 five-point questions. The test contains 10 three-point questions and 14 five-point questions. The test contains 14 three-point questions and 10 five-point questions. The test contains 20 three-point questions and 8 five-point questions.

Mathematics
2 answers:
Nikitich [7]3 years ago
6 0
X represents the number of 3-point questions.
y represents the number of 5-point questions.
The solution is (x, y) = (10, 14).

The test contains 10 three-point questions and 14 five-point questions.

Jet001 [13]3 years ago
4 0

x represents the number of 3-point questions.

y represents the number of 5-point questions.

The solution is (x, y) = (10, 14).


The test contains 10 three-point questions and 14 five-point question

hope this helps you

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A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches

The formula used to calculate the rectangular base of a rectangular pyramid =

Length × Width

Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

= 28 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (5 inches × 7.1 inches) ÷ 2

= 35.5 inches² ÷ 2

= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) Solving for d, it is important to note that, a rectangular pyramid has 5 faces and they are: The rectangular base and 4 triangular faces

The formula for the total surface area of the rectangular pyramid is given as

Total Surface Area of the rectangular pyramid = Rectangular Base + Area of Triangular Side A + Area of Triangular Side B + Area of Triangular Side C + Area of Triangular Side D + Area of Triangular Side E

Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

BRAINLIEST PLEASE?

3 0
3 years ago
If the legs of a right triangle are x, (2x - 1) and its hypotenuse is (2x + 1), what is the value of x?​
Ber [7]

Answer:

x=8

Step-by-step explanation:

(2x + 1)² = x² + (2x - 1)² = x² + (2x - 1)(2x - 1)

(2x + 1)(2x + 1) = x² + 4x²-2x-2x+1

4x²+2x+2x+1 = 5x²-4x+1

4x²+4x+1 = 5x²-4x+1

0= 5x²-4x²-4x-4x+1-1

0= x²-8x

x²-8x=0

x²=8x

x=8

3 0
3 years ago
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