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3 years ago

IS SOMEONE NICE ENOUGH TO HELP ME WITH THIS PLEASE? I"LL GIVE BRAINLIEST

Mathematics

1 answer:

ira [324]3 years ago

8 0

Answer:

$5,603.76

Step-by-step explanation:

For this problem you just need to plug in the number of years (5) for time then solve

$300(1.05)x^{12(5)} =5603.76$

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Question 9 of 15 (1 point)

mote1985 [20]

The number is -9

Step-by-step explanation:

Let x be the number then according to given statement

$4x+10 = x-17$

Subtracting 10 from both sides

$4x+10-10 = x-17-10\\4x = x-27$

Subtracting x from both sides

$4x-x = x-x-27\\3x = -27$

Dividing both sides by 3

$\frac{3x}{3} = \frac{-27}{3}\\ x = -9$

<u>Verification:</u>

$4(-9)+10 = -9-17\\-36+10=-26\\-26=-26$

The number is -9

Keywords: Linear equation, variables

Learn more about linear equation at:

#learnwithBrainly

7 0

2 years ago

Kelly and Jessica have a total of 5 same-sized cookies. They want to divide them equally between the two of them. How much cooki

Paraphin [41]

Answer:

Each girl gets 2 1/2.

Step-by-step explanation:

5 is an odd number. If you take the 4 in it and split that in half then you have 2. Then take the extra 1 from the rest of 5 and split that in half.

2 1/2.

5 0

3 years ago

Read 2 more answers

Why are u ugly sbadjBCBJXZBDFChd Sb çƒ√siub cvsxdhjb fsb zf jb

allochka39001 [22]

Answer:

आपको अपने पापों के लिए पश्चाताप करना चाहिए । वे तुम्हें नष्ट कर देंगे । आप कोई मौका नहीं खड़े हैं । तुम उसके हाथ पर मर जाओगे । पछताना

Step-by-step explanation:

its just so simple! :D

6 0

3 years ago

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Which statement is true about a dot plot?

natali 33 [55]

Answer:

Step-by-step explanation:

3 0

3 years ago

The gross domestic product (in billions of dollars) can be approximated by p(t)equals564 plus t left parenthesis 36 t supersc

nirvana33 [79]

We have been given gross domestic product (in billions of dollars) can be approximated by $P(t)=564+t(36t^{0.6}-101)$ .

(a) In this part, we need to compute the derivative of this function:

$P'(t)=\frac{d}{dt}(564+t(36t^{0.6}-103))\\P'(t)=\frac{d}{dt}(564)+\frac{d}{dt}(t(36t^{0.6}-103))\\P'(t)=0+57.6t^{0.6}-103\\$

$P'(t)=57.6t^{0.6}-103$

(b) In this part, we need to find the value of P'(45). So, we will substitute t=45

$P'(45)=57.6(45)^{0.6}-103\\P'(45)=565.3924-103\\P'(45)=462.39$ Billion dollars per year.

(c) P'(45)=462.39 represents that 45 years after 1960, that is, in 2005, the GCP was changing at a rate of 462.39 billion dollars per year.

4 0

3 years ago