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Pepsi [2]
3 years ago
9

IS SOMEONE NICE ENOUGH TO HELP ME WITH THIS PLEASE? I"LL GIVE BRAINLIEST

Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

$5,603.76

Step-by-step explanation:

For this problem you just need to plug in the number of years (5) for time then solve

300(1.05)x^{12(5)} =5603.76

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Solve for y and x<br> 2+3x-1=4y <br> And <br> 2x-3=y
Natasha_Volkova [10]

Answer:

x = 2.6, y = 2.2

Step-by-step explanation:

if 4y = 2 + 3x - 1 and

y = 2x - 3,

4y = 2 + 3x -1 and 4y = 8x - 12 so

8x - 12 = 2 + 3x - 1

so 5x - 12 = 1,

5x = 13,

x = 2.6

If x = 2.6,

y = 5.6 - 3

so y = 2.2

Please mark me as Brainliest!

6 0
2 years ago
What is a null set ?
forsale [732]
The existence proof of the empty set is an absolute gem
7 0
3 years ago
How do you do this?
Alenkasestr [34]

Answer:

by increasing the size ez

4 0
3 years ago
Find the value of Y! please help
Maurinko [17]

Answer:

y = 5.6

Step-by-step explanation:

Use Sine

Sine = \frac{opposite}{hypothenuse}

Sine 45 = \frac{y}{18}

Sine of 18 is 0.309

0.309 = \frac{y}{18}

Multiply 18 on both sides

0.309 x 18 = \frac{y}{18} x 18

5.562 = y

Round to the nearest tenth:

5.562 = 5.6

3 0
3 years ago
In Neil's city, the temperature is 72.6 degrees and is rising 1.3 degrees each hour. In Sheppard's city, the temperature is 80.4
klio [65]

Answer:

2.5 hours

Step-by-step explanation:

Given that :

Temperature in Neil's city :

72.6° and rising by 1.3° per hour

Temperature in Sheppard's city :

80.4° and dropping by 1.82° per hour

In how many hours will the temperature in Neil's city be no less than the temperature in Sheppard's city

Let number of hours = h

Hence, Neil city :

72.6 + 1.3h

Sheppard city:

80.4 - 1.82h

72.6 + 1.3h ≥ 80.4 - 1.82h

1.3h + 1.82h ≥ 80.4 - 72.6

3.12h ≥ 7.8

h ≥ 2.5

Two and half hours (2 hours 30 minutes)

8 0
3 years ago
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