If the ratio of the length to the breadth of a rectangle be 5:3 and its perimeter is 144m find the length of the rectangle

Mathematics

1 answer:

Kamila [148]2 years ago

5 0

Answer:

length=45 m (2 sides = 90m)

Step-by-step explanation:

5x +3x=144

8x=144

x=18 (each of the 8 parts of 144 measure 18m)

5(18) + 3(18)=144

90 +54=144

90/2=45 (1 length side)

54/2=27 (1 width side)

The rectangle= 45+45 +27+27 = 144

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What is least to greatest 2/8 2/1 3/4 5/6 7/6

yKpoI14uk [10]

Answer:

2/8, 3/4, 5/6, 7/6, 2/1

Step-by-step explanation:

To convert the fractions into ascending order (least to greatest):

1. Determine the LCM (Least common multiple) of the denominators.

2. Then, using the LCM, multiply such number to the denominators such that the product is equivalent to the LCM of the denominators.

Note: The number we multiply to the denominator must also be multiplied to the numerator.

3. Finally, create the set, in ascending order.

<h3>Determine the LCM of the denominators:</h3>

Given fraction set;

$\dfrac{2}{8} ; \ \dfrac{2}{1}; \ \dfrac{3}{4}; \ \dfrac{5}{6};\ \dfrac{7}{6}$

Therefore, the denominators of the fraction set are;

$\implies \text{Denominators: 8, 1, 4, 6, 6}$

Determining the LCM using Division method;

$\ \ \underline{................}\\2\underline{| 8, 1, 4, 6, 6}\\ 2\underline{|4, 1, 2, 3, 3} \\ 2\underline{|2,1,1,3,3} \\3 \underline{|1, 1,1,1,1}$

LCM of denominators: 2 × 2 × 2 × 3 = 24

<h3>Multiplying the denominators:</h3>

LCM of denominators: 24

<u>Multiply such number such that the denominators are equivalent to 24.</u>

$\implies \dfrac{2}{8} ; \ \dfrac{2}{1}; \ \dfrac{3}{4}; \ \dfrac{5}{6};\ \dfrac{7}{6}$

$\implies \dfrac{2 \times 3}{8 \times 3} ; \ \dfrac{2 \times 24}{1 \times 24} ; \ \dfrac{3 \times 6}{4 \times 6} ; \ \dfrac{5 \times 4}{6 \times 4} ; \ \dfrac{7 \times 4}{6 \times 4}$

$\implies \dfrac{6}{24} ; \ \dfrac{48}{24} ; \ \dfrac{18}{24} ; \ \dfrac{20}{24}; \ \dfrac{28}{24}$

<h3>Creating the set, in ascending order;</h3>

<u>Simply compare the fractions and put them in "smallest to biggest" order.</u>

$\implies \dfrac{6}{24} ; \ \dfrac{48}{24} ; \ \dfrac{18}{24} ; \ \dfrac{20}{24}; \ \dfrac{28}{24}$

$\implies \dfrac{6}{24} < \dfrac{18}{24} < \dfrac{20}{24} < \dfrac{28}{24} < \dfrac{48}{24}$

$\implies \dfrac{6}{24} \ \ \huge{\text{(}\dfrac{2}{8} } \text{)}; \ \dfrac{18}{24} \ \huge{\text{(}\dfrac{3}{4}\huge{\text{)} ; \ \dfrac{20}{24} \ \huge{\text{(}\dfrac{5}{6} \huge{\text{)} ; \ \dfrac{28}{24} \ \huge{\text{(} \dfrac{7}{6} \huge{\text{)}; \ \dfrac{48}{24} \ \huge{\text{(} \dfrac{2}{1} \huge{\text{)}$