Answer:
paying down high-interest credit cards.
NOT SURE BUT BELIEVE ITS THAT.
Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
Answer:
2.9 units
Step-by-step explanation:
Here the leg lengths are x and 7.7 and the one given angle is 21 degrees.
Think: which trig function incorporates both the length of the side opposite the 21 degree angle (x) and the vertical side (7.7)? It's the tangent function:
tan Ф = opp / adj
To be clear: the side adjacent (next to) the 21 degree angle is 7.7 units in length and the side opposite this angle is x.
Then we have tan 21 degrees = opp / adj = x / 7.7
and so 7.7(tan 21 degrees) = 7.7(03839) = 2.96 or (to one decimal place) 2.9
