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s2008m [1.1K]
2 years ago
6

What is the equation of the line through (4, 5) and (0, -3)?

Mathematics
1 answer:
madam [21]2 years ago
5 0

Answer: A. y= 2x-3

Step-by-step explanation: APEX,

Slope intercept equation of a line:

y = mx + b

(0, -3) is the y-intercept, so b = -3

We have

y = mx - 3

Now we use the two points to find the slope.

slope = m = (-3 - 5)/(0 - 4) = -8/(-4) = 2

y = 2x - 3

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Help me plz guys for 14 point​
strojnjashka [21]
I think its true, since perimeter is the diatance around. I would say mines correct, but you could try. I hope that helped atleast a little. :)
8 0
2 years ago
An equation is shown below:
IrinaK [193]
5(2x - 8) + 15 = -15
               -15      -15     subtract 15 from each side
5(2x - 8) = -30
  ÷5             ÷5             divide both sides by 5
2x - 8 = -6
     +8    +8                   add 8 to each side
2x=2
÷2  ÷2                          divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15             Correct! x=1
7 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through (1, 4) and (1, −3)?
Mazyrski [523]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 4) and (1, -3). Substitute:

m=\dfrac{-3-4}{1-1}=\dfrac{-7}{0}\qquad\boxed{!!!!}

DIVISION BY ZERO!!!

Answer: The slope is undefined.


It's a vertical line x = 1.

6 0
3 years ago
Is this the correct answer?
Step2247 [10]

Step-by-step explanation:

Close.  You correctly set up the integrals.  When integrating e²ˣ:

∫ e²ˣ dx

½ ∫ 2 e²ˣ dx

½ e²ˣ + C

So the coefficient should be ½, not 2.

[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹

[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]

1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1

-e⁻¹ + ½ e⁻² + ½ e² − e  + 1

8 0
3 years ago
Read 2 more answers
Answer please need help and is struggling
Mumz [18]
The answer is D (last one)
5 0
3 years ago
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