x = 16°
Step-by-step explanation:
The sum of angles in a straight line = 180°
Therefore
5x + 100° = 180°
5x = 180° - 100°
5x = 80°
x = 80/5
x = 16°
<u>Answer:
</u>
The diameter of a sphere is 6ft 6in. The radius of sphere is 3 feet 3 inches.
<u>Solution:
</u>
Given that the diameter of sphere is 6 feet 6 inches.
We have to find the radius of the sphere.
The relation between diameter and radius of sphere is given as

Therefore, 

Radius = 3 feet 3 inches.
Hence the radius of the sphere is 3 feet 3 inches.
Answer:
D
Step-by-step explanation:
We are given that:

And we want to find the value of tan(2<em>x</em>).
Note that since <em>x</em> is between π/2 and π, it is in QII.
In QII, cosine and tangent are negative and only sine is positive.
We can rewrite our expression as:

Using double angle identities:

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.
From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:
<h2>

</h2>
Simplify:

Evaluate:

The final answer is positive, so we can eliminate A and B.
We can simplify D to:

So, our answer is D.